(100x-50x^2)-(60x)=0

Solution for (100x-50x^2)-(60x)=0 equation:

(100x-50x^2)-(60x)=0

We get rid of parentheses

-50x^2+100x-60x=0

We add all the numbers together, and all the variables

-50x^2+40x=0

a = -50; b = 40; c = 0;
Δ = b2-4ac
Δ = 402-4·(-50)·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-40}{2*-50}=\frac{-80}{-100}
=4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+40}{2*-50}=\frac{0}{-100}
=0
$